My Last Question

[Former Member]

Hi

I am doing coding and right now its reached upto 700 line....and output is shortdump

error is CONVT_NO_ERROR.."*5.20" unable to interpret as Number....even i donknow how many variable i have taken..(bad progm practice)..in this program...what to do....:(. Pls help..how to reach to the exact variable.) i am doing debugging but problem lies in the loop.

thanks

[Former Member]

check the line number in the dump,

somewhere in an amoutn field amount value is stored as *5.20 , debug and checkout why the * is coming in front of that number

[Clemenss]

Hi subham arya,

in the dump, there is a source code section. The line where the error occurred is marked.

Are you sure it´was CONVT_NO_ERROR? I know CONVT_NO_NUMBER. This happens when moving charcters to a numeric field. You can bypass the error with

TRY

EXCEPT

ENDTRY

Search this forum for CONVT_NO_NUMBER.

Regards,

Clemens

[Former Member]

click on the "Information where terminated" section of the dump, where u can find the line number of the source code which raised the dump

[seshatalpasai_madala]

Hi,

I think the error is beacuse you have * in between quotes and you are trying to convert it to a number.

Check this out also if you can show us the code it will be easy to help you.

Regards,

Sesh

[dev_parbutteea]

Hi,

the * infront of your number might be occuring because you are trying to store a number longer than what the variable can store! you should change its lenght.

Regards,

Sooness.

[Former Member]

Hi Shubham,

You can see the detailed dump report(the dump log), there it is pointed out that the program is showing a short dump because of a particular line.

Put a break-point before this line of code. Debug the program starting from the break-point.

Possible cause of error is a type mismatch ie while equating a variable to another, type match may have been ignored.

<b>Reward points, if helpful.</b>

Regards,

Atin