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FINSTA01+ LOCKBOX

Former Member
0 Kudos

Hi All,

I have one doubt regarding how many times the particular segemnt repeated .

I am reading some data from EDIDC table and thern calling the FM ''IDOC_READ_COMPLETELY'

loop at i_EDIDC

call function module to collect the idoc information.

CALL FUNCTION 'IDOC_READ_COMPLETELY'

EXPORTING

document_number = itab-docnum

IMPORTING

idoc_control = edidc

TABLES

int_edids = i_edids

int_edidd = i_edidd

EXCEPTIONS

document_not_exist = 1

document_number_invalid = 2

OTHERS = 3

  • Loop at DATA Record to fill segment

LOOP AT i_edidd ASSIGNING <fs_edidd>.

CASE <fs_edidd>-segnam .

WHEN 'E1IDLB1' . " C_E1IDLB1 Make consatatn SAU

<fs_e1idlb1> = <fs_edidd>-sdata .

APPEND <fs_e1idlb1> TO i_e1idlb1.

CLEAR <fs_e1edpa1>.

WHEN 'E1EDPA1'.

<fs_e1edpa1> = <fs_edidd>-sdata.

APPEND <fs_e1edpa1> TO i_e1edpa1.

CLEAR <fs_e1edpa1>.

WHEN 'E1IDPU5'.

<fs_e1idpu5> = <fs_edidd>-sdata.

APPEND <fs_e1idpu5> TO i_e1idpu5.

CLEAR <fs_e1edpa1>.

ENDCASE. " case <fs_edidd>-segnam .

ENDLOOP. " LOOP AT i_edidd

ENDLOOP.

Here My Question is How many times the Segment E1IDLB1' & E1EDPA1' can be repeated for a single IDOC Num in I_EDIDC. I am sure segemnt 'E1IDPU5' will repeated multiple times for a single idoc num .But dont know abt other two segments.

I have to process some other function based on the value in the segments.

How can we create test data in WE19.

How can any one know that for a particular IDOC type a segment can be repated or not for a single IDOC Num.

Thanks a lot in Advance.

Best answer are always rewarded with points.

Regards

Saurabh T

1 REPLY 1

Former Member
0 Kudos

Go To Tranction WE60, and give FINSTA01 and check your segments.

E1lDLB1>1 times(Check Min/Max>number of segment you can repeat)

E1EDPA1-->2 times.

E1IDLB1 % ( IDoc: Lockbox Data/Account

Segment definition E2IDLB1 Released from Release 40A

Optional min./max. 0000000001/0000000001

E1EDPA1 % ( IDoc: Doc.item partner information

Segment definition E2EDPA1003 Released from Release 45A

Optional min./max. 0000000001/0000000002

Thanks,

Narayan