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kb31n and kp46 posting

Former Member
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Hi,

I would like to ask on skf related matter.

1) for both kb31n and kp46, only can define receiving cost center. no sender is needed here. correct? Then how to know from where the cost is coming?

2) For both kb31n (actual) and kp46 (plan), I assign the SKF to receiving cost center in both tcode. may i know how to execute so that i can get the cost in receiving cost center. I only can maintain the SKF to the receiving cost center only in these 2 tcode.

Thanks

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Answers (1)

Answers (1)

waman_shirwaicar
Active Contributor
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Hi,

The statistical key figures that you enter in KB31N would be used in assessment cycles (tcode KSU5) in the tracing factor.

Let me explain with an example:

You create an assessment cycle with:

  • "Variable portion"as Receiver rules,

  • "Actual Statistical Key figures" as Type of variable parts of tracing factor.

You choose as receiver a cost centre group which contains cost centres: let us call them A and B.

When you enter the values for the corresponding Statistical Key figure (transaction KB31N), you enter only values for the cost centre A and the cost centre B.

Then, when we run the cycle, the allocation of the sender cost centre X has only been done between the 2 cost centre A and B

So X is the sender and A and B are the receivers and the allocation depends on the SKF entered in KB31N

regards

Waman

Former Member
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Hi Waman,

Thanks alot.

Meaning in kb31n or kp46, we only to maintain SKF and quantity and receiver cost center, correct?

Sender only can maintain in cycle. correct?

Thanks

waman_shirwaicar
Active Contributor
0 Kudos

Hi,

Partly correct. In cycle you have to maintain both sender and receiver. In the tracing factors you can use the SKF so that system knows the proportion in which to allocate the values from sender to receiver.

You should try with a simple example in your test system to get a better undertstanding.

Using FB01 you can post say 100 EUR to cost center A

IN KB21N you can use SKF 25 for cost center B and 75 for cost center C.

Set up the cycle KSU1.

Run the cycle KSU5

Check the result

It should be

Cost center A = 100 - 100 = 0

Cost center B = 25

Cost center C = 75

regards

Waman