Wildcard in sharing reference?

[Former Member]

Hi,

We are about to start developing quite a few webservice consumers on the portal, and I would like to make a generic iview which reads the name of a service from a property value and outputs all methods it contains.

But in order to get the service I need a sharing reference, even for future services!

Is there any way to say, I want a sharing reference to all services ?

Or am I destined to write my own classloader and hack things

[Former Member · Accepted solution]

Hi Dagfinn,

using a wildcard * in the SharingReference doesn't work, at least not in the example I tried.

I would guess you need to implement your own classloader.

Regards

PD