on 05-10-2011 5:33 AM
Is there a way to base a test pass or fail on the average of measurements of a lot rather than pass or fail of a certain number of individual members.
In the situation I need to solve we have 4 tests to perform on a lot. The first three are rather straight forward, test individual serialized material and if x or y pass the test passes. In the last test the test results for the entire sample are taken, averaged, as well as some other calculations, and then based on the average the test passes or fails. The results of the individual material measurements are not evaluated as stand alone item.
Thank you for any help.
Regards,
Ron
Hi Ron,
What I have understood is, you want valuation of particular MIC on the basis of average of all readings and not as based on individual results.
To the best of my knowledge it is not feasible as rejection number and acceptance number are valuation deciding factors.
One thing you can do, you can go for manual valuation of MIC. After inputting several readings, system calculates the average. Check manually whether average falls under limits or not and valuate manually.
Regards,
Anand Rao
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"One thing you can do, you can go for manual valuation of MIC. After inputting several readings, system calculates the average. Check manually whether average falls under limits or not and valuate manually"
Where would I have the system calculate the average? On the standard screens I don't see anything that will calculate "down" a list of input values, only across from multiple inputs for one sample item.
Regards,
Ron
Hi Ron,
I try to explain.
1. Letu2019s say as per sampling procedure your sample size is 5. LENGTH (50mm u2013 55mm) is one of the MICs that you need to inspect.
2. Here you need to enter the readings 5 times. (provided you have opted single results in control indicators)
3. When you enter results one by one in QA32, system calculates average of these readings.
4. Check the phi symbol (ф)
5. System shows the average of readings against this symbol.
6. If you have entered results as 55, 50, 52.5, 54 and 53 your average would be 52.9 mm
Regards,
Anand Rao
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