I'm trying to grab the URL to load a different page. How would I go about doing this in a DynPage? I currently try to grab the page, but when I create a link from the output, it displays with page exception.
IPortalComponentURI componentURI = request.createPortalComponentURI();
componentURI.setContextName("com.test.demo_page");
String IVIEW_URL = componentURI.toString();
1 Answer
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Posted on Jul 21, 2004 at 11:31 AM
You might be able to use the URLGenerator service to generate a URL for the page
Have a look at the documentation for this service in the PDK
I hope this helps
D
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