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Former Member

Date / Time conversion

Hey

From a flat file i load data to a cube. Date and time is delivered in this format 19-07-2004 11:30:00. I need to convert the first part of the string into 0calday and the time part into a time characteristic with the format hhmmss. Is it nessecary to write a rutine to do this conversion, or is there a "simpler" way to do it?

Eagerly awaiting the best solution.

Chris

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1 Answer

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    Former Member
    Jul 20, 2004 at 10:19 AM

    Hai!

    You need to write a routine and you have no other option as per your requirement.

    But you can seprate them into different fields by modeifying the csv file to replace the space in beetween with the seperating caharecter like a ";" and read them as seperate fields in transfer rules.

    Ashwin

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