# How to display tiled sign when more then two decimal places

Hello Team,

We have received a requirement like below. Suppose we are printing one number field which contains the decimal places(i.e it may contain 2 or 4 or 10 or up to 14 decimal places).

My requirement is if the if the number contains more then two decimal places we need to display tiled symbol after two decimal places. Please let us know how can we achieve this.

Ex.

10.12354 is the original value

We need to display it like 10.12~

Thanks,

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• Dec 19, 2018 at 08:16 PM

I would use a formula to convert the number to a string, trim off trailing 0's, and then get the length of the part after the decimal point to determine whether to show the tile. The formula might look like this:

```{@ShowTile}
WhilePrintingRecords;
StringVar numstr := ToText({field},14, "",'.');
NumberVar i;
numstr := Split(numstr, '.')[2]; //get the part after the decimal
i := length(numstr);
Do While (i > 0) and (numstr[i] = 0)
i := i - 1;
Loop;
i > 2  //If there are more than 2 non-zero characters after the decimal point, return true, else return false```

Put your tile image on the report where it needs to be. Right-click on it and go to "Format object...". Click on the formula button to the right of the "Suppress" checkbox (DO NOT check the checkbox!) and enter the following:

not {@ShowTile}

This will suppress the image if the decimal length is 2 or less.

-Dell

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• Dec 20, 2018 at 02:12 PM

Create a formula with this code:

```numbervar x := {number_field}; //Replace this field with the number field from your data source
numbervar intg := int(x);
stringvar dec := strreverse(totext(tonumber(strreverse(split(totext(x,3),'.')[2])),'#'));
totext(intg,'#') & if dec <> '0' then '.' & left(dec,2) & if len(dec) > 2 then "~"```

-Abhilash

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• Dec 26, 2018 at 10:36 AM

Hello Abhilash,

Thanks for the replay we have tried it is working as expected up to 10 decimal places, but we need it for 14 decimal places. If we change from 10 to 12 getting an error like "crystal reports the number of decimal places is too large or not an integer". Please suggest us if you have any solution.

Thank you.