11-26-2009 8:34 AM
Hi experts,
I got a dynpro with a Input/output field on it which is set to output field only. There is also one button in the application toolbar with a function code "TEST".
When I double click the output field now, PAI is thrown and the function code is filled with 'TEST'. How can I avoid that?
The output field shouldn't be double clickable at all or at least throw a PAI with an empty function code.
Thanks in advance.
Regards,
Tobi
11-26-2009 8:48 AM
Hello,
When you created the TEST button on the application toolbar you probably have assigned the function key F2 to it. This automatically picks the double click action.
Delete the PF status and recreate it with a different function key assigned to the button (TEST) on the toolbar..
Regards,
Sachin
11-26-2009 8:48 AM
Hello,
When you created the TEST button on the application toolbar you probably have assigned the function key F2 to it. This automatically picks the double click action.
Delete the PF status and recreate it with a different function key assigned to the button (TEST) on the toolbar..
Regards,
Sachin
11-26-2009 9:12 AM
11-26-2009 8:49 AM
Hi,
Try clearing the function code i.e., sy-ucomm in PBO and check again.
Hope this helps you.
Regards,
Tarun