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Content Repository Identification

MTerence
Active Contributor
0 Kudos

Hi

While Creating Link in OAC3.... I am not able to give input for Cont. Rep. ID. In standard SAP it was given as A2, D3 etc. But when i enter these values, it says no values maintained. So, when i go to the customizing path, it goes to OAC0. If i give the content repository also, its not accepting....

Only two characters allowed...

I checked with the table TOAAR, same thing happens...

How to solve this query ....

Points for sure

- Pithan

Accepted Solutions (1)

Accepted Solutions (1)

Former Member

Hi,

In OAC0 while creating content repository give the name of content repository in 2 chars only.

Anirudh,

MTerence
Active Contributor
0 Kudos

Hi

Thank you for your reply

But i have already created content repository in two letters. But still its not picking up the particular respository...

i think some thing i have to maintain to get the link....

whats the customization required...

PL NOTE : When i double click the contents in the TCODE: OAC3 .. it said.. functions code cannot be selected

the error details...

how to solve this.. help me

+You entered an inactive function code.

You can trigger this by:

inputting directly in the OK code field

inputting the fastpath of an inactive menu function

choosing an inactive function key, or even by

choosing ENTER, if ENTER has an inactive function.

In batch input, a function code is included in field BDC_OKCODE of the session, as long as this function code is not assigned to ENTER.

As well as activating function codes statistically in the Menu Painter (Transaction SE41), they can also be deactivated dynamically using the EXCLUDING addition with statement SET PF-STATUS.+

- Pithan

Edited by: Pithan Pithan on Feb 13, 2009 12:09 PM

Former Member
0 Kudos

This is because you need to select ARCHLINK as document area while creating content repository.

It will then come into Edit Link.

Anirudh,

Answers (0)