Reduction in Scheduling

[Former Member]

Greetings........

i have one routing containg for header qty as 40 Number (40 no in lot). Opeartion are as follows :

Op.1 to Op. 6 for one day ( Start date 01.12.2008 & finish date 01.12.2008)

Op.7 to Op. 8 for one day ( Start date 02.12.2008 & finish date 02.12.2008)

Op. 9 for one day ( Start date 03.12.2008 & finish date 03.12.2008)

Op. 10 for three day (Start date 04.12.2008 & finish date 06.12.2008)

Op. 11 for two day (Start date 07.12.2008 & finish date 08.12.2008)

Op. 12 for one day (Start date 09.12.2008 & finish date 09.12.2008)

Op. 13 for one day (Start date 10.12.2008 & finish date 10.12.2008)

Like wise one lot get comapleted in (1113211) in *10 days

When first day lot after (Op.1 to Op,6) goes to second day , during second day work for op.7 to 8,

another 40 qty comes for Op. 1 to Op.6 parallel to Op. 7 to 8. like wise all over lap ocured , so at the end of 11 day i got another 40 qty. on 12th day i get another 40 qty ...so on.

i am geting 40 lot each day after first 10 day.

So how to map this overlaping in scheuling ...

pelase give your valuble input..

[Former Member]

closed

[Former Member]

Hi,

As per my understanding some of your operations are serial and some of them are parallel.But as per actual you scheduling the run time for a lot is 10 days.You wanted to say the when the op 7 and op 8 is going on the 1 to 6 operations (Work centers) are free means with 100% capacity.

As per me you need not to use reduction strategy which you cal maintain in OPUZ transaction.By maintaining maximum reduction level and % reduction in float.

As per me at the time of planning the capacity for the work centers of OP 1 to 6 will be zero after completion of 01.12.2008.The machines will be available for the next day.The scheduling for the orders will be lihe that....

Order 1 op1 to 6 01.12.2008

op7 to op8 02.12.2008

Order 2

Op1 to op6 02.12.2008

op7 to op8 03.12.2008 like wise.

Hope i am able to solve.

regards,

kaushik