* Commit work on table using UPDATE statement.*

[Former Member]

HI,

This is Anil . I have problem regarding Commit work and Wait up to 2 seconds.

I am using Commit work on one Update table statement but it is not working . While doing debugging it is working

(means it is updating Table.) but while running the transaction directly it is not updating the table.

Check the statements :

Commit work.

Some Select stmt on <table>.

IF <condition.>

Update <table > statement.

if sy-subrc EQ 0.

Commit work . ( This is not working while running transaction mean it is not updating table. While debuggint it it updating table.)

wait up to 2 seconds.

endif.

endif.

Will that above Commit work causing any problem or what is the reason it is not updating table.

Please give some suggestion in this case.

Regards,

Anilreddy.

[Former Member]

Hi

the below code with commit work is working finr for me.

only thing i suggest is to check sy-subrc value.

commit work.

update spfli set test = '1234' where carrid = 'AA'.

if sy-subrc eq 0.

commit work.

wait up to 2 seconds.

endif.

write: / sy-subrc.

[Former Member]

HI Jyothi ,

Thank you for your inputs . But my doubt is why it is not updating the table even if you use commit work, and wait up to 2 seconds.

Anil.

[former_member137336]

Anil,

Use the statement commit work and wait. This will solve your issue.

Regards

Farzan

[Former Member]

Hi,

Is this code is any user exit? or any update task, which may be failing?

If this is just an independent program, just use commit work. Should work . . . without wait also.

Best Regards,

[Former Member]

Hi Anil,

Why dont you try with one more second?

Wait upto 3 seconds. i have seen two or three programs in my system which waits for 3 seconds.

Might be based on the system's efficiency.