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Former Member
Aug 23, 2008 at 09:07 PM

Shift Operation Sequence

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Dear Friends,

I have a question regarding the duration of operations in PP Order.

Let's say, we have two operations, 1 and 2. Each of the operations has duration of 30 minutes, for example. When we have to make only one piece of finished good, we have to spend 1 hour. And it is correct.

But when we have to make 10 pieces of finished good, we don't have to wait untill we repeat the first operation 10 times before starting the second operation. Because after the firs piece has passed the first operation, it can be processed further. That way we spend only 330 minutes instead of 600 minutes.

Situation 1. - consecutive sequence

Operation1

| - - - - - - - - - - => 30min. X 10 pc = 300 min.

Operation2

| - - - - - - - - - - => 30min. X 10 pc = 300 min

=> Operation1+Operation2 = 600min ( all the pieces have passed through the first operation, then through the second one)

Situation 2. - consecutive-parallel sequence

Operation1

| - - - - - - - - - - =>30min X 10 pc = 300 min

Operation2

| - - - - - - - - - - =>30min X 10 pc = 300 min, BUT

Operation1+Operation2 = only 330 min! (after the first piece has passed Operation1, the two operations are processed in parallel)

Do you have any idea how to find some rule, some formula, that describes any case like the second situation? (As it is in the real life! 😊 )

Of course, any helpful answer will be generously regarded 😊

Thanks in advance!