Logic for this senerio -- UDF

[former_member638238]

Hi XI Gurus,

I hav to create a UDF.This is an IDOC - XI - FILE seerio. In this senerio is I have an IDOc whose 7th segment contains a field. This field can store values in between 0 - 9. On the other hand I have a file structure in my left hand side from Messge mapping prespective , which contains 9 similar sized fields.

Now the logic is if the field in the segment of the idoc has value say '3', then the file structure in the left hand side would have 3 in the field no 3 and all other fields 1, 2, 4, 5, 6, 7, 8, 9 would be zero.

Can u guys suggest some logic for this???

Thanks in advance !

Poits would be rewarded.

Arnab

[Former Member · Accepted solution]

Your requirement does not need any UDF, a simple if then else will help.

As you have clearly mentioned that the target has nine fields, so for the first field you define a constant and check if the input value equalS constant 1, if yes then pass input value else pass zero.

Similarly change the constant value for second field on the target side to 2 and do a similar if then else.

regards

sameer

[Former Member]

Hi,

1) Write folowing UDF

Type : Context

Input Value : field(segment containing field)

code :

for(int i = 0;i<field;i++)

{

if((i == 6)&&( field<i>.equals("3")))

{

result.addValue("true");

}

}

use ifWithOutElse standard function(Keeps == true)

2) Node file field 3 do following mapping

use ifWithOutElse standard function(Keeps == true)

field>UDF>ifWithOutElse(for 2nd value use constant contains value 3 )-->field 3

3) For all other nodes (1, 2, 4, 5, 6, 7, 8, 9 )

field>UDF>ifWithOutElse(for 2nd value use constant contains value 0 )-->field 3

Regards,

Rohit

Reward points if helpful.

[vijay_b4]

Hi Mohd,

Select the Queue option for getting individual nodes

public void test(String[] a,ResultList result,Container container){

if (a<i> == 7) { //This is for selecting the node

for(i=0;i<10;i++){ //This is for collecting the correct value

ifIi==3){

write what ever u have to done

}

else{

write the exceptional condition

}

}

}

Dont to Reward points if this helps

Regards

Pragathi.

}

[Former Member]

Hi,

You can do it using the existing Boolean unctions in Graphical Mapping.

Check the segment field value with a constant(0-9) and map it accordingly with every field on file structure side Using if else then .

Thanks,

Vijaya

[Former Member]

HI,

I don't think you need to go for UDF for this activity.

Source Field --->If Else(Verify if value is "1" else pass 0) ---> Field1

Similarly you can apply it for other fields also.

But as you had said * IDOc whose 7th segment contains a field*...and the IDOC have multiple occurance for the same segment and have to always refer 7th Segment then you need below code to be used in UDF.

Pass to UDF as

Source Segment ---> A

Field of Segment ---> B

Cache parameter as Queue

Copy paste below source code

if(Integer.parseInt(B[7]) == "1")

result.addValue(B[7]);

else

result.addValue(B[7]);

Similarly you have apply this logic for all the fields with modifying the value of UDF

Thanks

Swarup

[Former Member]

In the Standard Mapping function go to the Conversion.

and use "FixValues"

On the left hand side define 1 to 9 and on Right hand side define 0 for all and 3 for 3.

Other way to do is you can go to Boolean functions and use "if".

Gaurav Jain

**Points if answer is useful