Exceptions in SAX parser code

[Former Member]

how the arguments are used that i am passing through the "SAXException" constructor in the following example.

catch (IOException e) {

throw new SAXException("I/O error", e);

}

[Former Member · Accepted solution]

Hi Sankar,

how the arguments can be used while passing through SAXException, this you can learn very well in Java tutorials provided by sun java.

below are the link helpful to you these will describe you how to use arguments and also other help that might be useful for you.

1)This package provides the <b>core SAX APIs</b>.

http://java.sun.com/javase/6/docs/api/org/xml/sax/package-summary.html

2)This package contains interfaces to <b>SAX2 facilities</b> that conformant SAX drivers won't necessarily support.

http://java.sun.com/javase/6/docs/api/org/xml/sax/ext/package-summary.html

3)This package contains <b>"helper" classes</b>, including support for <b>bootstrapping SAX-based applications</b>.

http://java.sun.com/javase/6/docs/api/org/xml/sax/helpers/package-summary.html

hope this may solve your problem

Thanks

sandeep Sharma

PS: if helpful please reward points

[Former Member]

Hello Sankar,

Please frame the Question more properly.I didnt underestand what you have written.Could you pls re construct your Query

With Regards

Vidya

[GabrielSagaya]

hi

please go through the wiki

https://www.sdn.sap.com/irj/sdn/wiki?path=/display/snippets/java%2bsax%2bparser