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Kanban Calculation

Former Member
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Hey all

I have some problems regarding the formula for calculating the numbers of kanbans in SAP.

They use the same formula as in the theory, but they add a C which is default to the value of 1 (indicating that the container is registered as empty when the last piece is used).

Taking an example:

Demand = 10 pr day

Lead time = 2 days

Container size = 5

Safety factor = 50%

The container is empty when it is completely empty (C=1) - As in the theory!??

The theory would say that we need:

(DL (1+SF))/a = (102(1,5))/5 = 6 containers.

SAP says:

((RTAC)/CONT)SF + C = ((210)/5)1,5 + 1 = 7 kanbans

Why does the theory say that we need 65 = 30 units in the cycle and kanban says that we need 57 units?

If we set the constant to 0 we would get the right number, but in effect we would set the kanban to empty when it was almost full, so we would still get 5*6 = 30 kanbans + the kanban that is marked as empty but in reality is full.

Please help.

Thank you very much.

Message was edited by:

Nina Henriksen

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Answers (2)

Answers (2)

Former Member
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I figured it out myself.

former_member184627
Active Contributor
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Hi Nina,

In the calculation SF is 0.5 you have taken as 1.5.

((RTAC)/CONT)SF + C = ((210)/5)0,5 + 1 = 3 kanbans

Regards,

Senthilkumar

Former Member
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Hey Senthilkumar

I'm not sure that whast you are saying is correct, but even if it is it does not help me in regards to why the theory does not ude the same formaula as SAP. Now SAP says 3 kanbans before 7... the theory still says 6 kanbans...