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how open an external url with parameter from C4C

Aug 21, 2017 at 02:30 PM

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Hi Experts,

I need your suggestion.

Req. I need to open an external url with parameter from C4C. and the URL should open in the same window. It should not navigate to another window/tab/screen.

ex. www.google.co.in/q=1234

It should open in the same screen.

kindly help me to solve this req.

Regards,

Siva M

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2 Answers

Fabio Damasceno
Aug 24, 2017 at 11:45 AM
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Hello Siva,

Can you please tell us more about your scenario? For example, where from are you trying to create this URL (external application or from C4C itself)? Which parameter from C4C exactly?

We hope that this information will able us to continue the discussion. This thread (https://archive.sap.com/discussions/thread/3682370) seems to be related, so we would like to know more to proceed properly, Siva.

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Hi Fabio,

Thank you for your response.

Ex. I have a button to open the google maps, When i click the button. it should open the google map in same window which is currently C4C pages is ocupied.

When i click back, then C4C page should open

Regards,

Siva M

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Former Member Aug 31, 2017 at 03:27 PM
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Hi Siva,

you can use HTML Mashup to open URL with parameters in C4C screen.

https://blogs.sap.com/2016/08/03/creating-a-html-mashup-with-a-dynamic-url/

Regards,

Diego.

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10 |10000 characters needed characters left characters exceeded

Hi Diego,

Thank you for your response.

Ex. I have a button to open the google maps, When i click the button. it should open the google map in same window which is currently C4C pages is ocupied.

When i click back, then C4C page should open

Regards,

Siva M

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