Assigning values to a range dynamically

[Former Member]

Hello All,

I want to assign the values to a range dynamically.

For example in the following piece of code, I cannot directly assign wa-kunnr to

r_kunnr-low.

LOOP AT ITAB INTO WA.

r_kunnr-sign = 'I'.

r_kunnr-option = 'EQ'.

r_kunnr-low = wa-kunnr.

APPEND r_kunnr.

ENDLOOP.

Can this be done dynamically? If I use following code I am getting a short dump.

lv_fnam = 'wa-kunnr'.

LOOP AT ITAB INTO WA.

r_kunnr-sign = 'I'.

r_kunnr-option = 'EQ'.

r_kunnr-low = ( lv_fnam ).

APPEND r_kunnr.

ENDLOOP.

Could anyone please suggest how to do this?

Regards

Indrajit

[Former Member]

Hi Indrajit , try using Field symbols

field-symbols : <FS> type any.

assign (lv_fnam) to <FS>.

lv_fnam = 'wa-kunnr'.
LOOP AT ITAB INTO WA.
r_kunnr-sign = 'I'.
r_kunnr-option = 'EQ'.
r_kunnr-low = <FS>.
APPEND r_kunnr.
ENDLOOP.

[Former Member]

Hi Chandra,

Using field symbols, I am getting a short dump which says that I am trying to use an unassigned field symbol.

The statement

assign (lv_fnam) to <FS>

is not assigning the field symbol.

Indrajit.

[Former Member]

Hi Indrajit,

 this is working perfectly for me ...i did not get any error

REPORT  ychatest.

TABLES : kna1.

DATA : wa TYPE kna1,
       lv_fnam(10).

FIELD-SYMBOLS : <fs> TYPE ANY.

SELECT-OPTIONS : s_kunnr FOR kna1-kunnr.

INITIALIZATION.

  wa-kunnr = '100'.
  lv_fnam = 'WA-KUNNR'.
  ASSIGN (lv_fnam) TO <fs>.

  s_kunnr-sign = 'I'.
  s_kunnr-option = 'BT'.
  s_kunnr-low = <fs>.
  APPEND s_kunnr.

[Former Member]

Try:

lv_fnam = 'wa-kunnr'.
LOOP AT ITAB INTO WA.
  r_kunnr-sign = 'I'.
  r_kunnr-option = 'EQ'.
  r_kunnr-low = lv_fnam.
  APPEND r_kunnr.
ENDLOOP.

Rob

[Former Member]

Hi Rob,

I want the contents of wa-kunnr and not the text 'wa-kunnr' to be assigned to

r_kunnr-low .

Indrajit.

[Former Member]

Well, I don't see why you don't do it the first way.

rob