# How do you solve #log (3x+1) = 1 + log (2x-1)#?

##### 1 Answer

Dec 23, 2015

The explanation is given below.

#### Explanation:

Now we have to solve for x using inverse operaitions to isolate x.

*Adding 10 on both sides would remove #10# from the right side of the equation*

*Subtracting #3x# on both sides would isolate the term containing #x# to one side of the equation.*

*Dividing both sides by 17 we get*

**Answer**