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How to create/find the Pattern URL under Sender/Receiver REST communication channels

Former Member
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Hi Experts,

I have developed the scenario between Sender RFC to Receiver REST communication channels and Sender REST to Receiver RFC.

1) Question: RFC to REST:I have stuck where there tab

Define REST URL with URL pattern. In this URL pattern which URL should begiven by some one or should we need to create the URL. Please suggest on this.

2) Question for REST to RFC: How to create sender REST URL for further process.

Thanks in advance.

Regards

Sanjeev Kothwal

Accepted Solutions (0)

Answers (2)

Answers (2)

Muniyappan
Active Contributor
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Refer the documents in below link to know about sender and receiver rest adapter configuration.

https://blogs.sap.com/2014/12/18/pi-rest-adapter-blog-overview/

the url has to be given by rest service team. check with them by asking end url.

Meanwhile you can request that rest team to help you to test using rest tools such as soap ui or post man..this will give you an idea what needs to be given in channel.

Former Member
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Hi Muni/Experts,

Thanks for your answer.We have developed the scenario RFC<->PO<->REST, in this, we have configured RFC sender comm.channel and Receiver REST.

1) Question: How the Receiver(X system) third party system hit the URL to PO(XML to JSON) the server and how URL will hit from third party system.

2)Question: Do we needs to create Receiver REST Pattern URL or the third party(Target system) people will provide the URL for hitting the PO server.

3) Question: How do we can create Pattern URL for Sender REST communication channel.

Please help on this.

Regards,

Sanjeev K

Muniyappan
Active Contributor
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I assume you are asking below questions for REST to RFC scenario. Please check these post, it will provide you an idea how to contract the url.

https://blogs.sap.com/2016/03/25/sap-pipo-rest-sender-adapter-configuration-for-web-proxyodata-servi.../

https://blogs.sap.com/2014/12/18/pi-rest-adapter-exposing-a-function-module-as-restful-service/#post...

gurudatta
Participant
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Hi,

In the URL pattern give the URL of Service which you are going to call

Thanks,

Guru