identify dynamicly the last character of a character string

[Former Member]

Hello Dear!

Is there way to identify dynamicly the last character of a character string

e.g.

char a = 'hallooooooooo:)'.

the searched and find character is )

or

char b = '56565544fgfhjhgg#'.

the searched and find character is #.

Regards

Ilhan

[Former Member]

data : v_char(15) value  'hallooooooooo:)',
         v_last(1),
         v_len type i.

v_len = strlen( v_char ).
v_len = v_len - 1.

v_last = v_char+v_len(1).

write : v_last.

[former_member533584]

hi.

data

w_char type string.

w_strlen = strlen( w_char).

w_strlen = w_strlen - 1.

write w_char+w_strlen(1).

regards,

ananth.

[Former Member]

Hello,

Do like this:

DATA : V_FILE TYPE STRING .
DATA: LEN TYPE I.

V_FILE = ''56565544fgfhjhgg#'.

LEN = STRLEN( V_FILE ).
LEN = LEN - 1.
WRITE: V_FILE+LEN(1).

Output will be #

Regards,

Vasanth

[Former Member]

Hi,

use SHIFT v_STR circular.

then

v_letter = v_str+0(1).

regards,

anji

[Former Member]

Hi Ertas,

Calculate the length of character variable and get the last character.

DATA b(15) value '56565544fgfhjhgg#'.

data v_length type i.

v_length = strlen( b ).

write:/ 'Last character is: ', b+v_length(1).

Thanks,

Vinay

[Former Member]

Just a warning to everyone who has proposed an answer based on (string length - 1) as the offset, you also need to take care of the null string. Otherwise you may get a runtime errror.

So you need to put your code within if strelen > 0. endif.