Code for adding an integer to time

[prabhu_s2]

hi all

i have req in xi where i need to add '1' to current time. say if the vairable tme holds the current time and interger 1 is in constant integ what will be the piece of code to acieve this...i will be using it in a user def f/n.

ur expertise is requested

[Former Member · Accepted solution]

Wish the following piece code would help you.

for instance your constant is ONE_SECOND = 1 and the currentDate is the time variable.

Date currentDate = ...

long currentTime = currentDate.getTime();

long newTime = currentTime + ONE_SECOND*1000;

Date newDate = new Date( newTime);

Dennis

[prabhu_s2 · Accepted solution]

hi dennis

thks...lemme try

[prabhu_s2 · Accepted solution]

is this part not completed?

<i>Date currentDate = ...</i>

[prabhu_s2 · Accepted solution]

my current date will be in HH:mm:ss format and integer is 5 or 10. i nned to add this integer to the time which is in string format

[Former Member · Accepted solution]

Convert the string into a Date instance first.

SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");

Date currentDate = format.parse("You time string");

[Former Member · Accepted solution]

By the way when you say "I want to add the integer into the time", my understanding is that you want to add the integer to the second portion of a time.

For insance, original time is 12:30:20, if your integer is 5 or 10, then the final result would be 12:30:25 or 12:30:30. Is that correct?

[prabhu_s2 · Accepted solution]

say if i wanna to add 10 to 12:20:20 then it wud be 12:20:30 but if i add 40 then it wud be 12:21:00...this is the case. can u provide me the code for it

[prabhu_s2 · Accepted solution]

wud be gr8 if u can post the entire set of code

[Former Member · Accepted solution]

GregorianCalendar gc = new GregorianCalendar(2007,2,27,12,20,30 );
System.out.println("1." + gc.getTime());
gc.add(GregorianCalendar.SECOND,40);
System.out.println("2." +gc.getTime());

this gives me the following output on my PC...

1.Tue Mar 27 12:20:30 IST 2007
2.Tue Mar 27 12:21:10 IST 2007

[prabhu_s2 · Accepted solution]

thks ammal

but my input string STRG had an input 12:20:10 and another string inte has 10...i want to add this so that my output is 12:20:30...can u provide me the code for it

[Former Member · Accepted solution]

		String STRG = "12:20:10";
		String INTE = "10";
		StringTokenizer sTok = new StringTokenizer(STRG, ":");

		int hr = Integer.parseInt(sTok.nextToken());
		int min = Integer.parseInt(sTok.nextToken());
		int sec = Integer.parseInt(sTok.nextToken());

		GregorianCalendar today = new GregorianCalendar();

		GregorianCalendar gc =
			new GregorianCalendar(
				today.get(GregorianCalendar.YEAR),
				today.get(GregorianCalendar.MONTH),
				today.get(GregorianCalendar.DAY_OF_MONTH),
				hr,
				min,
				sec);
		System.out.println(gc.getTime());
		gc.add(GregorianCalendar.SECOND, Integer.parseInt(INTE));
		System.out.println(gc.getTime());

btw....12:20:10 +10 would be 12:20:20 and not 12:20:30

[prabhu_s2 · Accepted solution]

amol

one quick q...what will be the output for

String STRG = "12:20:59";

String INTE = "10";

can u pls check and post me...sorry i dont have access to nwds and xi now. unable to check it

[Former Member · Accepted solution]

must give you 12:21:09

[Sigiswald · Accepted solution]

What about not using custom string parsing

import java.sql.Time;
import java.util.Calendar;
import java.util.Date;

  // time in format "hh:mm:ss"
  private static String addSeconds(String time, String seconds) {
    Time t = Time.valueOf(time);
    Calendar c = Calendar.getInstance();
    c.setTime(t);
    c.add(Calendar.SECOND, Integer.parseInt(seconds));
    t.setTime(c.getTimeInMillis());

    return t.toString();
  }

Then

    System.out.println(addSeconds("12:20:10", "10")); // 12:20:20
    System.out.println(addSeconds("23:59:55", "10")); // 00:00:05

Kind regards,

Sigiswald