reading each character of a string

[Former Member]

hi all,

my requirement is :

i have a string 'NAKUL,AGARWAL'.

i want to read each alphabet of this string and then check if ',' comes ,i have to do certain coding and change it to '.'.

can you help me?

[Former Member]

data : v_name(15) value 'NAKUL,AGARWAL'.

search v_name for ','.
if sy-subrc eq 0.
  replace ',' with '.' into v_name.
endif.

[raymond_giuseppi]

Perhaps you could try any of these

REPLACE ',' WITH '.' INTO string.

SPLIT string at ',' INTO string1 string2.

regards

[Former Member]

Use REPLACE

REPLACE f ...WITH g

...INTO h.

[Former Member]

you can use search and replace .

else

data : len type i,

v_chr ,

pos type i.

compute len = strlen( str1 ).

do len times.

v_chr = str1+pos(1).

if v_chr = ','.

<do coding>

endif.

pos = pos + 1.

enddo.

regards

shiba dutta

[Former Member]

refer demo code

Character occurance in a String -

PARAMETERS : P_CHAR TYPE C LOWER CASE.

data str type string.

dATA: LEN TYPE I,

COUNT TYPE I,

PASS TYPE I VALUE '0'.

str = 'amita'.

CONDENSE STR.

LEN = STRLEN( STR ).

DO LEN TIMES.

IF P_CHAR = STR+pass(1).

COUNT = COUNT + 1.

ENDIF.

pass = pass + 1.

ENDDO.

[jayanthi_jayaraman]

Hi,

v1 = 'NAKUL,AGARWAL'.

Replace all occurrences of ',' with '.' in v1.

[Former Member]

Hi Nakul,

Check the code for u r requirement,

REPORT ZEX31 .

PARAMETER : str1(20) .

DATA : v2(20),

d TYPE i,

e TYPE i,

f TYPE i.

d = 0.

e = 0.

f = strlen( str1 ).

WHILE d NE f.

IF str1+d(1) ne ','.

v2e(1) = str1d(1).

d = d + 1.

e = e + 1.

ELSE.

v2+e(1) = '.'.

e = e + 1.

d = d + 1.

ENDIF.

ENDWHILE.

write : / str1.

write : / v2.

[Former Member]

thanks a lot guys for the answers

[Former Member]

Hi,

use this statement,

replace all occurences of ',' with '.' in v_string.

Regards,

Aman