on 10-04-2015 2:05 AM
Hi,
Yes Agree. Make sure to use the conditions using the BRF plus table with the combinations you had speciifed.
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Hello Indraneel,
Thank you for your response!
I have following questions regarding incompatibilities
- How system interprets evaluation results in conditions and incompatibility definitions.
Scenario1:
Condition5 | Condition6 | ||
Product |
| MOT |
|
FRUITS | 1 | CHILLED | 1 |
FLOWERS | 1 | DRY | 1 |
|
| ||
Defination3 |
|
|
|
Condition5 | 1 | Condition6 | 1 |
If FU is with fruits Evl.result would be 1 form condition5 and for MOT – Chilled Evl.result would be 1, then control goes to definition and finds 1 & 1 are incompatible, so now incompatibility evaluation decides FRUITS are incompatible with CHILLED MoT.
Sceanrio2:
FLOWERS can go into CHILLED but can’t go into DRY FRUITS can’t go into CHILLED but can go into DRY. | |||
Defination3 |
|
|
|
Condition5 | Condition6 | ||
Product |
| MOT |
|
FRUITS | 1 | CHILLED | 0 |
FLOWERS | 1 | DRY | 1 |
|
| ||
Defination3 |
|
|
|
Condition5 | 1 | Condition6 | 1 |
- If FU with FLOWERS Evl.result would be 1 form condition5 and for MOT – CHILLED Evl.result would be 0, then control goes to definition and finds 1 & 1, then decide FLOWERS can go into CHILLED.
- If FU with FLOWERS Evl.Result would be 1 from condition5 and for MOT – DRY Evl.result would be 1 then control goes to definition and finds 1 & 1, then decides FLOWERS can’t go into DRY
Yes, above two results are as required by the business.
When it comes to Fruit
- If FU with FRUITS Evl.result would be 1 from condition5 and for MOT- CHILLED Evl.result would be 0, then then control goes to definition and finds 1 & 1, decides FRUITS can go into CHILLED
- IF FU with FRUITS Ev.Result would be 1 from condition5 and MOT-DRY Evl.result would be 1, in definition Evl.result is 1 & 1, decides FRUITS can’t go into DRY, but business case is - FRUITS can’t go into CHILLED
Possible solution:
Create a new set of conditions and definition as below
FLOWERS can go into CHILLED but can’t go into DRY | |||
Defination3 |
|
|
|
Condition5 | Condition6 | ||
Product |
| MOT |
|
FLOWERS | 1 | DRY | 1 |
|
| ||
Defination3 |
|
|
|
Condition5 | 1 | Condition6 | 1 |
FRUITS can’t go into CHILLED but can go into DRY. | |||
Defination3 |
|
|
|
Condition7 | Condition8 | ||
Product |
| MOT |
|
FRUITS | 1 | CHILLED | 1 |
|
| ||
Defination3 |
|
|
|
Condition5 | 1 | Condition6 | 1 |
Question:
Regards,
Gupta
Hi,
Kindly check this discussion thread as enclosed in the attachment since I am not been able to copy paste the thread.
Kindly let me know if this is requires further clarification.
Basically you can enter one condition and select the values- Identical values only and in this way you can define an incompatibility between two instances of same business object.Also to group together No of conditions you can group multiple combinations using incompatability type.
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