on 11-18-2014 11:32 PM
Hi Experts, I have 20 Data Flows in One Work Flow, Each Data Flow creates one file in CSV format, my requirement is the file name for the CSV should be name followed by current date For Example like TEST-2014_11_18 should be created Suggesion Please Thanks
Hi Uhdam,
Below process could help you.
Hope this helps you meet requirement.
Regards
Santhosh
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
HI Uhdham Reddy,
PLease select 'answered' to track the thread
it was correctlyanswered. You
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Thanks everyone for your effort, i have already implemented the above logics, that was not my requirement As per your suggesion, every dataflow will have a script and the script and dataflow should be in workflow If i put script in front of every data flow in Workflow that has 30 data flow it looks weared
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi Uhdam,
In the script type the following code:
$G_CurrentDate= sysdate();
print($G_CurrentDate);
$G_Filename= 'TEST_'||$G_CurrentDate||'.csv';
print($G_Filename);
Declare the variable $G_CurrentDate as date and $G_Filename as varchar.
Place this variable $G_Filename in the File name(s) of the File Format Editor.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
As par as I know, This is not possible.
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
User | Count |
---|---|
84 | |
10 | |
10 | |
9 | |
7 | |
6 | |
5 | |
5 | |
4 | |
4 |
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.