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split the value using comma as delimiter and then pass each value to query to get the description

Hi,

As i am new to crystal reports, I need help in getting one field.

In my report i am using 2 tables:

one is like :

code_id code_desc 1 aaa 2 bbb 3 ccc 4 ddd

and the another is :

reason_ind 1 2,3,4 2,3 1,2,3,4 3,4

In this report i have a column : Reason_desc.

Here i have to show code_desc for those values of reason_ind matches with code_id in the above table.

Ex:

reason_ind reason_desc 1 aaa 2,3,4 bbb,ccc,ddd 2,3 bbb,ccc

Let me know if you need further clarifications.

Thanks in advance.

Regards,

Swathi.

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  • Best Answer
    Posted on Jul 21, 2014 at 09:03 AM

    Hi Swathi,

    Here's how you can do this at the report level:

    1) Create a Main report pointing to the second table from that screenshot.

    2) Drag and drop the Reason_ind column on the Details Section

    3) Insert a Subreport pointing to the First table and place it on the Details Section

    4) Right-click the Subreport > Select Change Subreport Links > Move the Reason_Ind field to the pane on the right > Uncheck the option 'Select data in Subreport based on field'

    5) Get inside the Subreport and go to Report > Selection Formulas > Record and use this code:

    ToText({Code_Id},0,"") IN Split({@Pm-Reason_Ind},",")

    6) In the Subreport, create a Group on the Code_Desc field

    7) Suppress the Report Header, Group Header, Details and Group Footer sections

    8) Create a Formula with this code and place it on the Group Header 1 section:

    whileprintingrecords;

    stringvar s := s + {Code_Desc} + ", ";

    9) Create one more formula and place this on the Report Footer section:

    whileprintingrecords;

    stringvar s;

    Left(s,len(s)-2);


    Hope this helps.


    -Abhilash


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