Converting time into integer

Hi Aima,

Have two char and two integer varaibles.

1. Move the Start Time and End time to char variables.

2. Move the char values to integer variables.

3. Now subtract Endtime from Start time to get total.

Regards,

Rajasekhar

One question, in what unit is the integar value to be. You have two times, do you need to see the difference in hours/minutes/seconds? If not, what could you possibly be trying to do?

As you can see in this sample program, the difference between the times is 59 mintues.

report zrich_0001.


data: time1 type sy-uzeit,
      time2 type sy-uzeit,
      time_diff type sy-uzeit.

   time1 = '095800'.
   time2 = '085900'.


   time_diff = time1 - time2.

   write:/ time1,
         / time2,
         / time_diff.

Regards,

Rich Heilman

What are you trying to get, difference between the times in seconds, or minutes, or hours or all? If you declare the tot as type i(integer), then you will get the difference as the number of seconds, or if you define tot as another time field, then you will get it time format HHMMSS.

Srinivas

I prefer to use TimeStamps for this sort of thing, especially if you must cross days.

The following is an example from 640 that uses the new cl_abap_tstmp class.

 cl_abap_tstmp=>systemtstmp_syst2utc(
        exporting
          syst_date = <wa_joblist>-strtdate
          syst_time = <wa_joblist>-strttime
        importing
          utc_tstmp = start_stamp ).

      cl_abap_tstmp=>systemtstmp_syst2utc(
        exporting
          syst_date = sy-datum
          syst_time = sy-uzeit
        importing
          utc_tstmp = now_stamp ).

      seconds = cl_abap_tstmp=>subtract(
          tstmp1 = now_stamp
          tstmp2 = start_stamp ).

From the help on 'COMPUTE':

DATA: SECONDS TYPE I, 
      TIME_FROM TYPE T VALUE '200000', 
      TIME_TO   TYPE T VALUE '020000'. 
SECONDS = ( TIME_TO - TIME_FROM ) MOD 86400. 

SECONDS has the value 21600 (6 hours). The "MOD 86400" operation in this example ensures that the result is not negative, even if the time period spans midnight.

Rob

Hi Aima,

How to determine of the times(Beg,End) are on the same date? Ignore my earlier post.

As srinivas suggested, post the code, how you are getting the beg and end times...plz

Regards,

Raj

Use Function Module SD_CALC_DURATION_FROM_DATETIME

It returns a DEC 11 value. It also returns a parameter tells you which of the 2 dates is greater.

Hi Rich

<b>.98 means the difference is .98 of an hour.</b>

From my understanding it is .98 Hours.

<b>@Srinivas</b>

<b>Difference between two time fields is always an integer value.</b>

Yes , if u declare as resultant variable as type i then it is,but for me i have received as 0.98 hours .

for the difference of 08:59 and 09:59.

0.98 08:59 09:58