hi,
I hava the following problem.
In one of my tables within a web dynpro I have one column with urls (e.g http://www.google.com").
what I want to do is to open the url with an external browser window, dependent on which row is selected.
with the code:
IWDWindow window= wdControllerAPI.getComponent().getWindowManager().createExternalWindow(
"STRING" ,"google",true);
I can open a browser window, but only if I hardcode the url. If I want to use a variable (e.g. url) from my table:
String URL = wdContext.currentLinkListMapElement().getURL();
I get a
com.sap.tc.webdynpro.services.exceptions.WDRuntimeException: Invalid URL=http://www.url.de
exception.
please please help
thanx
Christoph