Resource URL or Relative path.

[Former Member]

Hi ,

In my webdynpro view i have a LinkToUrl button.I want to supply a URL to this button property Reference.

I have a HTML file in KM under documents/mydocs/test.html

my coding looks like this

IWDClientUser wdClientUser = WDClientUser.getCurrentUser();

com.sap.security.api.IUser sapUser = wdClientUser.getSAPUser();

IUser ep5User = WPUMFactory.getUserFactory().getEP5User(sapUser);

IResourceContext resourceContext = new ResourceContext(ep5User);

IResourceFactory resourceFactory = ResourceFactory.getInstance();

RID pathRID = RID.getRID(wdContext.currentContextElement().getPath());

IResource resource = resourceFactory.getResource(pathRID, resourceContext);

after this coding,i dont know how to get the URL or full path.I have checked getTargetUrl but it returns null.

Can someone help me with this. ??

[Former Member · Accepted solution]

The complete path is

"http://server:port/irj/servlet/prt/portal/prtroot/com.sap.km.cm.docsdocuments/mydocs/test.html"

You can also omit the "http://server:port" part.

You can get all the documents inside the folder by the following

IResource resource = resourceFactory.getResource(ridpath,

resourceContext);

// cast the object to a Collection

ICollection collection = (ICollection) resource;

// get the Collection's children

IResourceList resourceList = collection.getChildren();

// and finally get an iterator to walk through the set of children

IResourceListIterator resourceListIterator = resourceList.listIterator();

while (resourceListIterator.hasNext()) {

// … and create a new context element for each of them

IResource tempResource = resourceListIterator.next();

fileName = tempResource.getName();

}

You can refer this weblog

free to ask more

award points. if useful.

Geogi

[Former Member · Accepted solution]

Thanks Geogi,

I have this info already.i have also gont through this blogs but these are not helping in my case.

[Former Member · Accepted solution]

Hi Baskaran

Using this you can provide the link and clicking the link document get opened

Regards

Geogi

[Former Member · Accepted solution]

Hi

This is the code for opening the document on clicking the link.The body of the function is below.

IWDWindow newwindow = wdComponentAPI.getWindowManager().createExternalWindow( "http://<servername>:<port>/irj/servlet/prt/portal/prtroot/com.sap.km.cm.docs"wdContext.currentContextElement().getPath()"/"+name,"from km repository",false);

newwindow.open();

(Here Path=/documents/mydocs and variable name=test.html)

Regards

Geogi

[Former Member · Accepted solution]

Please don't hardcode this stuff. Use IURLGeneratorService instead.

[Former Member · Accepted solution]

Hi Julian,

Can you please give me some code snipet for this

[Former Member · Accepted solution]

Try something like:

      IURLGeneratorService generator = (IURLGeneratorService)ResourceFactory.getInstance().getServiceFactory().getService(IServiceTypesConst.URLGENERATOR_SERVICE);
      IUriReference target = generator.getRelativeUri(PathKey.CONTENT_ACCESS_PATH).appendPath(res.getRID().toExternalForm());

[Former Member · Accepted solution]

Thanks Julian.

This is what i was looking for.It works the way i wanted,you are Great.